p^2-4p-26=0

Solution for p^2-4p-26=0 equation:

p^2-4p-26=0

a = 1; b = -4; c = -26;
Δ = b2-4ac
Δ = -42-4·1·(-26)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{30}}{2*1}=\frac{4-2\sqrt{30}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{30}}{2*1}=\frac{4+2\sqrt{30}}{2}
$